MCQ
For a symmetrical frequency distribution, we have
- Amean $<$ mode $<$ median
- Bmean $>$ mode $>$ median
- ✓mean $=$ mode $=$ median
- Dmode $=\frac{1}{2}($ mean + median $)$
✓
Answer
Correct option: C.
mean $=$ mode $=$ median
(c)
We must have, mean $=$ mode $=$ median.
We must have, mean $=$ mode $=$ median.
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