MCQ
For an event $E , P ( E )+ P (\overline{ E })=x$, then the value of $x^3-3$ is
- ✓-2
- B2
- C1
- D-1
✓
Answer
Correct option: A.
-2
(a)
Given
$
P(E)+P(\overline{E})=x
$
Also, according to the law of probability,
$
P(E)+P(\bar{E})=1
$
From (i) and (ii), we get $
x=1
$
Put value of $x$ in $x^3-3$, we get
$
x^3-3=(1)^3-3=1-3=-2
$
Given
$
P(E)+P(\overline{E})=x
$
Also, according to the law of probability,
$
P(E)+P(\bar{E})=1
$
From (i) and (ii), we get $
x=1
$
Put value of $x$ in $x^3-3$, we get
$
x^3-3=(1)^3-3=1-3=-2
$
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