MCQ
For any integer $n,$ the integral  $\int_0^\pi {{e^{{{\sin }^2}x}}{{\cos }^3}(2n + 1)x\,dx = } $
  • A
    $ - 1$
  • $0$
  • C
    $1$
  • D
    $\pi $

Answer

Correct option: B.
$0$
b
(b) Let $f(x) = \int_0^\pi {{e^{{{\sin }^2}x}}{{\cos }^3}(2n + 1)x.dx} $

Since $\cos (2n + 1)(\pi - x) = \cos [(2n + 1)\pi - (2n + 1)x]$

$ = - \cos (2n + 1)x$ and ${\sin ^2}(\pi - x) = {\sin ^2}x$

Hence by the property of definite integral,

$\int_0^\pi {{e^{{{\sin }^2}x}}{{\cos }^3}(2n + 1)x\,dx = 0} $, $[f(2a - x) = - f(x)]$.

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