Download App

Sets — MATHS STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceMATHSSets1 Mark
MCQ
For any two sets A and B, A−(A−B) equals:
  • A
    B
  • B
    A − B
  • C
    A ∩ B
  • D
    AC ∩ BC
✓

Answer

  1. A ∩ B

Solution:

Now, A − (A − B) = A − (A ∩ BC)

= A ∩ (A ∩ BC)C

= A ∩(AC ∪ B)

= (A ∩ AC) ∪ (A ∩ B)

= A ∩ B

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Sets→Sets — all question types→MATHS STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

Which term of G.P. 25, 125, 625, …………. is 390625?
→
If $A + B + C =\pi$, then the value of $\tan \left(\frac{ A + B }{2}\right)$ is :
→
If A = {1, 2, 4}, B = {2, 4, 5}, C = {2, 5}, then (A - B) × (B - C) is:
  1. {(1, 2), (1, 5), (2, 5)}
  2. {(1, 4)}
  3. (1, 4)
  4. none of these.
→
Let R be set of points inside a rectangle of sides a and b (a, b > 1) with two sides along the positive direction of x-axis and y-axis. Then
→
The maximum distance between points $ (3\sin \theta, 0, 0)$ and $(4\cos \theta, 0, 0)$ is:
→
Solve – x2 + x – 2 = 0.
→
The general solution of the equation $7\cos^2\text{x}+3\sin^2\text{x}=4$ is:
  1. $\text{x}=2\text{n}\pi\pm\frac{\pi}{6},\text{n}\in\text{Z}$
  2. $\text{x}=2\text{n}\pi\pm\frac{2\pi}{3},\text{n}\in\text{Z}$
  3. $\text{x}=\text{n}\pi\frac{\pi}{3},\text{n}\in\text{Z}$
  4. None of these
→
Choose the correct answer.

The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1 : 4 are:

    →
    if $\text{f}(\text{x})=1+\text{x}+\frac{\text{x}^2}{2}+\dots+\frac{\text{x}^{100}}{100},$then f'(1) is equal to:
    →
    If A and B are two sets such that n(A) = 17, n(B) = 23, n(A ∪ B) = 38, find n(A ∩ B):
    →