MCQ
For complete neutralization of $HCl$ with $NaOH,$ the heat of neutralization is ......$kJ\,mo{l^{ - 1}}$
- A$ + 13.70$
- B$ - 13.70$
- ✓$ - 57.32$
- D$ + 57.32$
✓
Answer
Correct option: C.
$ - 57.32$
(c)Heat of neutralization of strong acid and strong base is equal to the $ - 57.32\,KJ\,mo{l^{ - 1}}$
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