Download App

Statistics — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsStatistics1 Mark
MCQ
For drawing a frequency polygon of a continuous frequency distribution, we plot the points whose ordinates are the frequency of respective classes and abscissa are respectively:
  • ✓
    Class marks of the classes.
  • B
    Lower limits of the classes.
  • C
    Upper limits of the classes.
  • D
    Upper limits of preceeding classes.
✓

Answer

Correct option: A.
Class marks of the classes.
Frequency polygon is the line graph plotted with class marks on $x-$axis $\&$ frequency of the class on $y-$axis.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q" from Statistics→Statistics — all question types→Maths STD 9 question papers→Gujarat Board STD 9 question papers→Gujarat Board question paper generator→

Similar questions

The sides of a triangle are 11 m, 60 m and 61 m. The altitude to the smallest side is
→
In a cricket match, a batsman hits a boundary $6$ times out of $30$ balls he plays. What is the probability that in a given delivery, the ball does not hit the boundary$?$
→
The factors of $12 x^2-x-6$ are:
→
An exterior angle of a triangle is $110^\circ $ and its two interior opposite angles are equal. Each of these equal angles is:
→
After rationalising the denominator of $\frac{7}{3 \sqrt{3}-2 \sqrt{2}}$, we get the denominator as
→
The volume of a cylinder of radius $r$ is $\frac{1}{4}$ of the volume of a rectangular box with a square base of side length $x$. If the cylinder and the box have equal heights, what is $r$ in terms of $x$?
→
In the given figure, equilateral $\triangle A B C$ is inscribed in a circle and $\ce{ABCD}$ is a quadrilateral, as shown. Then, $\angle BDC =$ ?
Image
→
Pythagoras was a student of:
→
Write the correct answer in the following: The point at which the two coordinate axes meet is called the:
→
In the following, write the correct answer. $D$ is point on the side $BC$ of a $\triangle\text{ABC}$ such that $AD$ bisects Then.
→