MCQ
For electron in '$2 s$' and '$2 p$' orbitals, the orbital angular momentum values, respectively are :
  • A
    $\sqrt{2} \frac{\mathrm{~h}}{2 \pi}$ and 0
  • B
    $\frac{\mathrm{h}}{2 \pi}$ and $\sqrt{2} \frac{\mathrm{~h}}{2 \pi}$
  • C
    0 and $\sqrt{6} \frac{\mathrm{~h}}{2 \pi}$
  • D
    0 and $\sqrt{2} \frac{\mathrm{~h}}{2 \pi}$

Answer

D. 0 and $\sqrt{2} \frac{\mathrm{~h}}{2 \pi}$
Orbital angular momentum $=\sqrt{\ell(\ell+1)} \frac{\mathrm{h}}{2 \pi}$
$\therefore \quad$ For 2 s orbital $: \ell=0$
Orbital angular momentum $=0$
$\therefore$ For 2 p orbital $: \ell=1$
$\begin{aligned} \text { Orbital angular momentum } & =\sqrt{1(1+2)} \frac{ n }{2 \pi} \\ & =\sqrt{2} \frac{h}{2 \pi}\end{aligned}$

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