For every positive integer n, n^2-n is divisible by - Vidyadip

MCQ

For every positive integer $n, n^2-n$ is divisible by

A
$6$
✓
$2$
C
$8$
D
$4$

✓

Answer

Correct option: B.

$2$

$n^2-n = n(n - 1)$.
Since $n$ and $(n - 1)$ are consecutive integers.
Therefore, one of them must be divisible by $2.$

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