MCQ
HCF of two consecutive even numbers is
- A
- B1
- ✓2
- D4
✓
Answer
Correct option: C.
2
(c)
Let the two consecutive even numbers be 2 n and $(2 n+2)$.
Prime factorisation of $2 n =2 \times n$
Prime factorisation of $(2 n+2)=2 \times(n+1)$
To find HCF, we multiply all the prime factors common to both numbers
Therefore, HCL = 2
Let the two consecutive even numbers be 2 n and $(2 n+2)$.
Prime factorisation of $2 n =2 \times n$
Prime factorisation of $(2 n+2)=2 \times(n+1)$
To find HCF, we multiply all the prime factors common to both numbers
Therefore, HCL = 2
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