Question
For frictionless surfaces in given arrangement tension $T_2$ is :-

Answer

$a=\frac{2 m g}{m+2 m+3 m}=\frac{g}{3}$

$\mathrm{T}_{2}=\mathrm{m} \times \mathrm{a}=\mathrm{m} \times \mathrm{g} / 3$

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