MCQ
For $n = 3$ energy level, the number of possible orbitals (all kinds) are
  • A
    $1$
  • B
    $3$
  • C
    $4$
  • $9$

Answer

Correct option: D.
$9$
d
(d) When $n = 3$ shell, the orbitals are ${n^2} = {3^2} = 9$ .

No. of electrons $ = 2{n^2}$

Hence no. of orbital $ = \frac{{2{n^2}}}{2} = {n^2}$.

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