MCQ
$C{{H}_{3}}-CH=CH-C{{H}_{3}}\underset{\left( Anti-Markownikoff's\text{ }addition \right)}{\mathop{\xrightarrow[{{R}_{2}}{{O}_{2}},\Delta ]{HBr}}}\,$
Comment on optical activity of the products
- ✓Racemic
- BDiastereomer
- CMeso
- DOptically pure enantiomer


