MCQ
For $ns$ orbital, the magnetic quantum number has value
- A$2$
- B$4$
- C$-1$
- ✓$0$
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Assertion $A$ : The first ionization enthalpy for oxygen is lower than that of nitrogen.
Reason $R$ : The four electrons in $2 p$ orbitals of oxygen experience more electron-electron repulsion.
In the light of the above statements, choose the correct answer from the options given below.
$(I)\, [Co(NO_2)_3(NH_3)_3]$
$(II)$ cis $-[ RhCl_2 (NH_3)_4]^+$
$(III)\, [Cr(OX)_3]^{-3}$
$(IV)$ cis $ -[PtCl_2 (en)]$
$(V)$ trans $-[Cr(en)_2 Br_2]^+$
$(VI)$ cis $-[Cr(en)_2 Br_2]^+$