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6.1. Equilibrium - 1 (chemical Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.1. Equilibrium - 1 (chemical Equilibrium)1 Mark
MCQ
For reaction : $SO _2( g )+\frac{1}{2} O _2( g ) \rightleftharpoons SO _3( g )$ $K _{ P }=2 \times 10^{12}$ at $27^{\circ}\,C$ and 1 atm pressure. The $K _{ c }$ for the same reaction is $.........\times 10^{13}$. (Nearest integer)

(Given $R =0.082\,L\,atm\,K ^{-1}\,mol ^{-1}$ )

  • A
    $2$
  • B
    $3$
  • C
    $4$
  • ✓
    $1$
✓

Answer

Correct option: D.
$1$
d
$SO _{2( g )}+\frac{1}{2} O _{2( g )} \rightleftharpoons SO _{3( g )}$

$K _{ P }=2 \times 10^{12} \text { at } 300\,K$

$K _{ P }= K _{ C } \times( RT )^{\Delta n _{ g }}$

$2 \times 10^{12}= K _{ C } \times(0.082 \times 300)^{-1 / 2}$

$K _{ C }=9.92 \times 10^{12}$

$K _{ C }=0.992 \times 10^{13}$

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