Question
For the AP 0.6, 1.7, 2.8, 3.9 ........, write the first term and the common difference.
✓
Answer
0.6, 1.7, 2.8, 3.9...
First term = a= 0.6
Common difference (d) = Second term -First term
= Third term - Second term and so on
Therefore, Common difference (d) = 1.7−0.6=1.1
First term = a= 0.6
Common difference (d) = Second term -First term
= Third term - Second term and so on
Therefore, Common difference (d) = 1.7−0.6=1.1
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Is the given statement correct or not correct?
If a die is thrown, there are two possible outcomes- an odd number or an even number. Therefore, the probability of getting an odd number is $\frac{1}{2}$.
→If a die is thrown, there are two possible outcomes- an odd number or an even number. Therefore, the probability of getting an odd number is $\frac{1}{2}$.
The circumference of a circle is 22cm. find the area of its quadrant.
Very-Short-Answer Question:
Find the zeros of the polynomial $x^2 + x - p(p + 1).$
→Find the zeros of the polynomial $x^2 + x - p(p + 1).$
In figure, $\triangle ABC$ is circumscribing a circle. Find the length of $BC$ .
→The sum of first n terms of an A.P. whose first term is 8 and the common difference is 20 is equal to the sum of first 2n terms of another A.P. whose first term is -30 and common difference is 8. Find n.
Prove that $\frac{1}{\sqrt{2}}$ is irrational.
→Show that the progressions given below is an AP. Find the first term, common difference and next term.
$-1,\frac{-5}{6},\frac{-2}{3},\frac{-1}{2},....$
→$-1,\frac{-5}{6},\frac{-2}{3},\frac{-1}{2},....$
Find the distance between the points:
$A(9, 3)$ and $B(15, 11)$
→$A(9, 3)$ and $B(15, 11)$
Prove the following trigonometric identities.
$\tan\theta+\frac{1}{\tan\theta}=\sec\theta\text{cosec}\theta$
→$\tan\theta+\frac{1}{\tan\theta}=\sec\theta\text{cosec}\theta$
Find the value of a so that the point $(3, a)$ lies on the line represented by $2 x-3 y+5=0$
→