MCQ
For the circuit shown in the fig., the current through the inductor is $0.9\,A$ while the current through the condenser is $0.4\,A$. Then
- Acurrent drawn from generator $I = 1.13 \,A$
- B$\omega = 1/(1.5\,LC)$
- ✓$I = 0.5\, A$
- D$I = 0.6\, A$
✓
Answer
Correct option: C.
$I = 0.5\, A$
c
The current drawn by inductor and capacitor will be in opposite phase. Hence net current drawn from generator
The current drawn by inductor and capacitor will be in opposite phase. Hence net current drawn from generator
$= I_L -I_C = 0.9 -0.4 = 0.5\,amp.$
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