For the ellipse x^2 64 + y^2 28 = 1, the eccentricity is - Vidyadip

MCQ

For the ellipse $\frac{{{x^2}}}{{64}} + \frac{{{y^2}}}{{28}} = 1$, the eccentricity is

✓
$\frac{3}{4}$
B
$\frac{4}{3}$
C
$\frac{2}{{\sqrt 7 }}$
D
$1\over3$

✓

Answer

Correct option: A.

$\frac{3}{4}$

a
(a) ${e^2} = 1 - \frac{{{b^2}}}{{{a^2}}}$

${e^2} = \frac{{36}}{{64}}$

==> $e = \frac{3}{4}$.

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