MCQ
For the equilibrium
$2{H_2}O \rightleftharpoons {H_3}{O^ + } + O{H^ - }$ ,
the value of $\Delta {G^o}$ at $298\,K$ is approximately .......$kJ\,mol^{-1}$
- A$100$
- B$-80$
- ✓$80$
- D$-100$
✓
Answer
Correct option: C.
$80$
c
$\Delta {G^o} = - 2.303RT\,\log \,{K_{eq}}$
$\Delta {G^o} = - 2.303RT\,\log \,{K_{eq}}$
$ = - 2.303 \times 8.314 \times 298\,\log \,{10^{ - 14}}$
$ = - 2.303 \times 8.314 \times 298 \times - 14$
$ = 79,881.87$
$ \simeq 80\,KJ\,mo{l^{ - 1}}$
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