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6.1. Equilibrium - 1 (chemical Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.1. Equilibrium - 1 (chemical Equilibrium)1 Mark
MCQ
For the following reactions, equilibrium constants are given

$S\left( s \right) + {O_2}\left( g \right) \rightleftharpoons S{O_2}\left( g \right);{K_1} = {10^{52}}$

$2S\left( s \right) + 3{O_2}\left( g \right) \rightleftharpoons 2S{O_3}\left( g \right);{K_2} = {10^{129}}$

The equilibrium constant for the reaction $2S{O_2}\left( g \right) + {O_2}\left( g \right) \rightleftharpoons 2S{O_3}\left( g \right)$ is

  • A
    $10^{77}$
  • ✓
    $10^{25}$
  • C
    $10^{181}$
  • D
    $10^{154}$
✓

Answer

Correct option: B.
$10^{25}$
b
$2S{O_2}(g) + {O_2}(g) \to 2S{O_3}(g)$

${K_{eq}} = \frac{{{{[S{O_3}]}^2}}}{{[{O_2}]{{[S{O_2}]}^2}}}$

$ = \frac{{{K_2}}}{{{K_1}}} = \frac{{{{10}^{129}}}}{{{{10}^{104}}}} = {10^{25}}$

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