MCQ
For the function $f(x) = {e^x},a = 0,b = 1$, the value of $ c$ in mean value theorem will be
- A$log \,x$
- ✓$\log (e - 1)$
- C$0$
- D$1$
==> $\frac{{{e^b} - {e^a}}}{{b - a}} = f'(c)$
==>$\frac{{e - 1}}{{1 - 0}} = {e^c} \Rightarrow c = \log (e - 1)$.
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$(P)$ If $A \neq I_{2},$ then $|A|=-1$
$(\mathrm{Q})$ If $|\mathrm{A}|=1,$ then $\operatorname{tr}(\mathrm{A})=2$
where $I_{2}$ denotes $2 \times 2$ identity matrix and $\operatorname{tr}(A)$ denotes the sum of the diagonal entries of $A$ Then