MCQ
For the function $f(x) = {e^x},a = 0,b = 1$, the value of $ c$ in mean value theorem will be
  • A
    $log \,x$
  • $\log (e - 1)$
  • C
    $0$
  • D
    $1$

Answer

Correct option: B.
$\log (e - 1)$
b
(b) Here $\frac{{f(b) - f(a)}}{{b - a}} = f'(c)$

==> $\frac{{{e^b} - {e^a}}}{{b - a}} = f'(c)$

==>$\frac{{e - 1}}{{1 - 0}} = {e^c} \Rightarrow c = \log (e - 1)$.

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