MCQ
For the gas phase reaction,

$PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$

which of the following conditions are correct ?

  • A
    $\Delta H < 0$ and $\Delta S < 0$
  • B
    $\Delta H > 0$ and $\Delta S < 0$
  • C
    $\Delta H = 0$ and $\Delta S < 0$
  • $\Delta H > 0$ and $\Delta S > 0$

Answer

Correct option: D.
$\Delta H > 0$ and $\Delta S > 0$
d
Gas phase reaction

$\mathrm{PCl}_{5(\mathrm{g})}=\mathrm{PCl}_{3(\mathrm{g})}+\mathrm{Cl}_{2(\mathrm{g})}$

$\Delta \mathrm{H}=\Delta \mathrm{E}+\Delta \mathrm{n}_{\mathrm{g}} \mathrm{RT}$

$\Delta n_{g}=$ Change in number of moles of product and reactant species.

since $\Delta n_{g}=+v e,$ hence $\Delta H=+v e$

also one mole of $\mathrm{PCl}_{5}$ is dissociated into two moles of $\mathrm{PCl}_{5}$ and $\mathrm{Cl}_{2}$ in the same phase.

Therefore, $\Delta S=S_{\text {product }}-S_{\text {reactant }}$

$\Delta S=+v e$

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