Correct option: D.$\Delta H > 0$ and $\Delta S > 0$
d
Gas phase reaction
$\mathrm{PCl}_{5(\mathrm{g})}=\mathrm{PCl}_{3(\mathrm{g})}+\mathrm{Cl}_{2(\mathrm{g})}$
$\Delta \mathrm{H}=\Delta \mathrm{E}+\Delta \mathrm{n}_{\mathrm{g}} \mathrm{RT}$
$\Delta n_{g}=$ Change in number of moles of product and reactant species.
since $\Delta n_{g}=+v e,$ hence $\Delta H=+v e$
also one mole of $\mathrm{PCl}_{5}$ is dissociated into two moles of $\mathrm{PCl}_{5}$ and $\mathrm{Cl}_{2}$ in the same phase.
Therefore, $\Delta S=S_{\text {product }}-S_{\text {reactant }}$
$\Delta S=+v e$