For the given circuit the current through battery of $6\,V$ just after closing the switch ' $S$ ' will be$.......A$.
A$3$
B$2$
C$0$
D$1$
JEE MAIN 2022, Medium
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D$1$
d Just after closing the switch $S$, inductor behaves
like an open circuit.
$I=\frac{6}{2+4}=1\,A$
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