MCQ
For the given reactions

$Sn ^{2+}+2 e ^{-} \rightarrow Sn$

$Sn ^{4+}+4 e ^{-} \rightarrow Sn$

The electrode potentials are; $E _{ Sn ^{2+} / Sn }^{\circ}=-0.140\, V$ and $E _{ Sn ^{4+} / Sn }^{\circ}=0.010\, V$. The magnitude of standard electrode potential for $Sn ^{4+} / Sn ^{2+}$ i.e. $E _{ Sn ^{4+} / Sn ^{2+}}^{\circ}$ is $.....\times 10^{-2}\, V$. (Nearest integer)

  • A
    $320$
  • B
    $32$
  • $16$
  • D
    $160$

Answer

Correct option: C.
$16$
c
$Sn ^{2+}+2 e ^{-} \rightarrow Sn \quad \Delta G _{1}^{0}=+2 \times 0.140 \times F$

$Sn ^{+4}+4 e ^{-} \rightarrow Sn \quad \Delta G _{2}^{0}=-4 \times 0.01 \times F$

____________________________________________

$Sn ^{+4}+2 e ^{-} \rightarrow Sn ^{+2} \quad \Delta G _{3}^{0}=-2 \times E _{ Sn ^{+4} / Sn ^{+2}}^{0} \times F$

$\Delta G _{3}^{0}=\Delta G _{2}^{0}-\Delta G _{1}^{0}$

$-2 \times E ^{0} \times F =-(0.04+0.28) \times F$

$E ^{0}=0.16$ volt $=16 \times 10^{-2} \,V$

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