present.
$\mathrm{AB}(\mathrm{g}) \rightleftharpoons \mathrm{A}(\mathrm{g})+\mathrm{B}(\mathrm{g})$
Number of moles at $t_{0} 1 \quad 0 \quad 0$
Number of moles at $\mathrm{t}_{\mathrm{eq.}} 1-\frac{1}{3}=\frac{2}{3}$ $\frac{1}{3} \frac{1}{3}$
After dissociation, total number of moles $\frac{2}{3}+\frac{1}{3}+\frac{1}{3}=\frac{4}{3}$
p is the total pressure.
The partial pressure of AB
$\mathrm{p}_{\mathrm{AB}}=\frac{2 / 3}{4 / 3} \times \mathrm{p}=\frac{\mathrm{p}}{2}$
The partial pressures of A and B are $\mathrm{p}_{\mathrm{A}}=\mathrm{p}_{\mathrm{B}}=\frac{1 / 3}{4 / 3} \times \mathrm{p}=\frac{\mathrm{p}}{4}$
$\mathrm{K}_{\mathrm{p}}=\frac{\mathrm{p} \mathrm{A} \mathrm{p} \mathrm{B}}{\mathrm{p}_{\mathrm{AB}}}$
$\mathrm{K}_{\mathrm{P}}=\frac{\frac{\mathrm{p}}{4} \times \frac{\mathrm{p}}{4}}{\frac{\mathrm{p}}{2}}$
$\mathrm{K}_{\mathrm{p}}=\frac{\mathrm{p}}{8}$
$\mathrm{p}=8 \mathrm{K}_{\mathrm{p}}$
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