MCQ
For the reaction ${H_2}(g) + \frac{1}{2}{O_2}(g)\,\, \to \,\,{H_2}O(l),\,\Delta H = - 285.8\,\,kJ\,\,mo{l^{ - 1}}$ $\Delta S = - 0.163\,kJ\,mo{l^{ - 1}}{K^{ - 1}}.$ What is the value of free energy change at ${27\,^o}C$ for the reaction ......$kJ\,mo{l^{ - 1}}$
  • $ - 236.9$
  • B
    $ - \,281.4$
  • C
    $ - \,334.7$
  • D
    $ + 334.7$

Answer

Correct option: A.
$ - 236.9$
(a)$\Delta G = \Delta H - T\Delta S\,\,\,,\,T = 27 + 273 = 300\,K$
$\Delta G = ( - 285.8) - (300)( - 0.163) = - 236.9\,kJ\,mo{l^{ - 1}}$

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