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For the reaction ${N_{2(g)}} + 3{H_{2(g)}}$ $\rightleftharpoons$ $2N{H_{3(g)}}$, the correct expression of equilibrium constant $K$ is

• ✓
  $K = \frac{{{{[N{H_3}]}^2}}}{{[{N_2}]{{[{H_2}]}^3}}}$
• B
  $K = \frac{{[{N_2}]{{[{H_2}]}^3}}}{{{{[N{H_3}]}^2}}}$
• C
  $K = \frac{{2[N{H_3}]}}{{[{N_2}] \times 3[{H_2}]}}$
• D
  $K = \frac{{[{N_2}] \times 3[{H_2}]}}{{2[N{H_3}]}}$