MCQ
For the reaction taking place in the cell:

$Pt ( s )\left| H _{2}( g )\right| H ^{+}( aq ) \| Ag ^{+}( aq ) \mid Ag ( s )$

$E _{\text {Cell }}^{0}=+0.5332 V$.

The value of $\Delta_{ f } G ^{0}$ is $kJ \,mol ^{-1} \cdot$ (in nearest integer)

  • A
    $5$
  • B
    $96$
  • $51$
  • D
    $57$

Answer

Correct option: C.
$51$
c
$\frac{1}{2} H _{2}+ Ag ^{+} \rightarrow H ^{+}+ Ag$

$\Delta G ^{\circ}=- nE ^{\circ} F$

$=-1 \times 0.5332 \times 96500 \,J$

$=-51.35 \,kJ$

$\left( n =2 \text { for } H _{2}+2 Ag ^{+} \rightarrow 2 H ^{+}+2 Ag \right)$

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