Download App

6.1. Equilibrium - 1 (chemical Equilibrium) — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistry6.1. Equilibrium - 1 (chemical Equilibrium)1 Mark
MCQ
For the reactions

$A\, \rightleftharpoons \,B$                     ${K_C} = 2$

$B\, \rightleftharpoons \,C$                    ${K_C} = 3$

$C\, \rightleftharpoons \,D+E$               ${K_C} = 5$

$K_C$ for the reaction $A\, \rightleftharpoons \,D+E$ is

  • A
    $2 + 3 + 5$
  • B
    $\frac{{2 \times 3}}{5}$
  • C
    $\frac{{5 \times 3}}{2}$
  • ✓
    $2 \times 3 \times 5$
✓

Answer

Correct option: D.
$2 \times 3 \times 5$
d
By adding all the three reactions, we will get target reaction. On adding reaction, there equilibrium constant will be multiplled

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 6.1. Equilibrium - 1 (chemical Equilibrium)→6.1. Equilibrium - 1 (chemical Equilibrium) — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

When electron jumps from $n = 5$ to $n = 2$ with all possible transitions then correct answer is
→
Silicon has a strong tendency to form polymers like silicones. The chain length of silicone  polymer can be controlled by adding :-
→
$(A)$ $HOCl + H _{2} O _{2} \rightarrow H _{3} O ^{+}+ Cl ^{-}+ O _{2}$

$(B)$ $I _{2}+ H _{2} O _{2}+2 OH ^{-} \rightarrow 2 I ^{-}+2 H _{2} O + O _{2}$

Choose the correct option.

→
How many representations of lactic acid are possible in Fischer projection $(d $ & $l)$ ?
→
Which is wrong about complex $[HgI_3]^{-1}$
→
Number of moles of ${K_2}C{r_2}{O_7}$ reduced by one mole of $S{n^{2 + }}$ ions is
→
The oxidation state of chlorine in $KCl{O_4}$ is
→
Solubility of $Ba{F_2}$ in a solution $Ba{(N{O_3})_2}$ will be represents by the concentration term
→
Carbon and silicon belong to $(IV)$ group. The maximum coordination number of carbon in commonly occurring compounds is $4$, whereas that of silicon is $6$. This is due to
→
In the following groups

$\begin{array}{*{20}{c}}{ - OAc}\\{\rm{I}}\end{array}$$\begin{array}{*{20}{c}}{ - OMe}\\{{\rm{II}}}\end{array}$$\begin{array}{*{20}{c}}{ - OS{O_2}Me}\\{{\rm{III}}}\end{array}$$\begin{array}{*{20}{c}}{ - OS{O_2}C{F_3}}\\{{\rm{IV}}}\end{array}$

The order of leaving group ability is

→