MCQ
For the system $3A + 2B$ $\rightleftharpoons$ $C$, the expression for equilibrium constant is
- A$\frac{{[3A][2B]}}{C}$
- B$\frac{{[C]}}{{[3A][2B]}}$
- C$\frac{{{{[A]}^3}{{[B]}^2}}}{{[C]}}$
- ✓$\frac{{[C]}}{{{{[A]}^3}{{[B]}^2}}}$
$K = \frac{{[C]}}{{{{[A]}^3}{{[B]}^2}}}$.
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| Element | Ionization | enthalpy | $(kJ/mol)$ |
| $1^{st}$ | $2^{nd}$ | $3^{rd}$ | |
| $A$ | $899$ | $1757$ | $14847$ |
| $B$ | $737$ | $1450$ | $7731$ |
Which of the following statements is correct ?
$Mn{O_2}(s)\, + \,4{H^ + }(aq)\, + \,2{e^ - }\, \to \, M{n^{ + 2}}(aq)\, + \,2{H_2}O(l)\,;$ $E_2^o\, = \,1.21\,\,V$
$MnO_4^{ - 1}(aq)\, + \,4{H^ + }(aq)\, + \,3{e^ - }\, \to \, Mn{O_2}(s)\, + \,3{H_2}O(l)\,;$ $E_3^o\,?$
value of $E_3^o$ will be ............ $\mathrm{V}$
$2MnO_4^ - + 5{C_2}O_4^{2 - } + 16{H^ + } \to 2M{n^{2 + }} + 10C{O_2} + 8{H_2}O$
Here $20\,ml$ of $0.1\,M$ $KMn{O_4}$ is equivalent to