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Question Bank [2022] — Maths (commerce) STD 12 Commerce / Arts — Question

Maharashtra BoardEnglish MediumSTD 12 Commerce / ArtsMaths (commerce)Question Bank [2022]4 Marks
Question
Form the differential equation from the relation $x^2+ 4y^2= 4b^2$
✓

Answer

Given relation is
$
x^2+4 y^2=4 b^2
$
Differentiating w.r.t. $x$, we get
$
2 x+4.2 y \frac{ d y}{ d x}=0
$
$\therefore x+4 y \frac{ d y}{ d x}=0$, which is the required differential equation.

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