Question
Form the pair of linear equations in the following problems, and find their solution graphically:
$5$ pencils and $7$ pens together cost Rs. $50$, whereas $7$ pencils and $5$ pens together cost Rs. $46.$ Find the cost of one pencil and a pen.

Answer

Let the number of pencils and pens be $x$ and $y$ respectively.
According to questions.
$5x + 7y = 50 .......(i)$
$7x + 5y = 46 ........(ii)$
From (i), $\text{y}=\frac{50-5\text{x}}{7}\ ......(\text{iii})$
Putting $x = 3$ in $(iii)$, we get $Y = 5$
Putting $x = -4$ in $(iii)$, we get $Y = 10$
$x$
$3$
$-4$
$Y$
$5$
$10$


From $(ii)$, $\text{y}=\frac{46-7\text{x}}{5}\ ......(\text{iv})$
Putting $x = 3$ in $(iv)$, we get $y = 5$
Putting $x = -2$ in $(iv)$, we get $y = 12$
$x$
$3$
$-2$
$y$
$5$
$12$
Thus, from graph cost of pencil $= Rs. 3$ and cost of pen$= Rs. 5.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Find the area of a quadrant of a circle hose circumference is$ 44\ cm.$
Solve the following systems of equations:
$\frac{4}{\text{x}}+3\text{y}=14,$
$\frac{1}{3\text{x}}-4\text{y}=23.$
When the triangle is revolved about the side $BC$, then the base-radius, height and slant height of the produced cone becomes $AB, BC$ and $AC$ respectively. Therefore, the volume of the produced cone is
Prove the following identities:
$\frac{\tan\text{A}+\tan\text{B}}{\cot\text{A}+\cot\text{B}}=\tan\text{A}\tan\text{B}$
A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears
  1. a two-digit number
  2. a perfect square number
  3. a number divisible by 5.
Solve the following systems of equations:
$\frac{44}{\text{x}+\text{y}}+\frac{30}{\text{x}-\text{y}}=10,$
$\frac{55}{\text{x}+\text{y}}+\frac{40}{\text{x}-\text{y}}=13.$
Evaluate the following:
$\frac{4}{\cot^230^\circ}+\frac{1}{\sin^260^\circ}-\cos^245^\circ$
In tha given fingure, $ABCD$ is a trapezium of area $24.5cm^2$. $24.5cm^2$ If $\text{AD}||\text{BC},\ \angle\text{DAB}=90^\circ,\ \text{AD}=10\text{cm},\ \text{BC}=4\text{cm}$ and ABE is quadrant of a circle then find the area of the shaded region. $\Big[\text{Use }\pi=\frac{22}{7}\Big]$
Prove the following identities:
$\frac{\big(1+\tan^2\theta\big)\cot\theta}{\text{cosec}^2\theta}=\tan\theta$
If $\alpha$ and $\beta$ are the zeroes of the quadratic polynomial $f(x) = x^2+ px + q,$ find a quadratic polynomial whose zeroes are $(\alpha+\beta)^2$ and $(\alpha-\beta)^2.$