MCQ
Formation for ammonia is shown by the reaction ${N_{2(g)}} + 3{H_{2(g)}} \to 2N{H_{3(g)}},{\Delta _r}{H^o} =  - 91.8\,kJ\,mo{l^{ - 1}}$ What will be the enthalpy of reaction for the decomposition of $NH_3$ according to the reaction $2N{H_{3(g)}} \to {N_{2(g)}} + 3{H_2};{\Delta _r}{H^o} = ?$ .....$ kJ\, mol^{-1}$
  • $-91.8$
  • B
    $+91.8$
  • C
    $-45.9$
  • D
    $+45.9$

Answer

Correct option: A.
$-91.8$
a
$\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{NH}_{3}(\mathrm{g}) \quad \Delta_{\mathrm{r}} \mathrm{H}^{\circ}=-91.8 \,\mathrm{kJ\,mot}^{-1}$

$2 \mathrm{NH}_{3(\mathrm{g})} \rightarrow \mathrm{N}_{2(\mathrm{g})}+3 \mathrm{H}_{2}(\mathrm{g}) \Delta_{\mathrm{r}} \mathrm{H}^{\circ}=+91.8 \,\mathrm{kJ\,mol}^{-1}$

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