Four identical cells of $EMF$ $E$ and internal resistance $r$ are connected as shown in figure, find terminal voltage across any one cell
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Current in the circuit $I=\frac{4 E}{4 r}=\frac{E}{r}$
Terminal potential $\quad \mathrm{V}=\mathrm{E}-\mathrm{Ir}$
$=\mathrm{E}-\frac{\mathrm{E}}{\mathrm{r}} \times \mathrm{r}=0$
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