Four metallic plates each of surface area (of one side) $A$, are placed at a distance $d$ apart from each other. The two outer plates are connected to a point $P$ and the two inner plates are connected to another point as shown in figure below. Then, the capacitance of the system is
A$\varepsilon_0 \frac{A}{2 d}$
B$\varepsilon_0 \frac{A}{d}$
C$2 \varepsilon_{0} \frac{A}{d}$
D $3 \varepsilon_{0} \frac{A}{d}$
KVPY 2009, Medium
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C$2 \varepsilon_{0} \frac{A}{d}$
c (c)
Above system is equivalent to two capacitors in parallel,
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