MCQ
Four particles each of mass $m$ are placed at the vertices of a square of side $l.$ The potential energy of the system is
  • A
    $ - \frac{{\sqrt 2 G{m^2}}}{l}\left( {2 - \frac{1}{{\sqrt 2 }}} \right)$
  • $ - \frac{{2G{m^2}}}{l}\left( {2 + \frac{1}{{\sqrt 2 }}} \right)$
  • C
    $ - \frac{{\sqrt 2 G{m^2}}}{l}\left( {\sqrt 2  + \frac{1}{{\sqrt 2 }}} \right)$
  • D
    $ - \frac{{2G{m^2}}}{l}\left( {\sqrt 2  - \frac{1}{{\sqrt 2 }}} \right)$

Answer

Correct option: B.
$ - \frac{{2G{m^2}}}{l}\left( {2 + \frac{1}{{\sqrt 2 }}} \right)$
b
$PE = \frac{{ - 4G{m^2}}}{l} - \frac{{2G{m^2}}}{{\sqrt 2 l}} =  - \frac{{2G{m^2}}}{l}\left( {\sqrt 2  + \frac{1}{{\sqrt 2 }}} \right)$

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