MCQ
A stone of mass of $16\, kg$ is attached to a string $144 \,m$ long and is whirled in a horizontal circle. The maximum tension the string can withstand is $16$ Newton. The maximum velocity of revolution that can be given to the stone without breaking it, will be ....... $ms^{-1}$
  • A
    $20 $
  • B
    $16$
  • C
    $14 $
  • $12$

Answer

Correct option: D.
$12$
d
(d) Maximum tension = $\frac{{m{v^2}}}{r} = 16N$

$⇒$ $\frac{{16 \times {v^2}}}{{144}} = 16$

$⇒ v = 12\, m/s$

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