Four wires of equal length and of resistances $10$ $ ohms$ each are connected in the form of a square. The equivalent resistance between two opposite corners of the square is ............. $ohm$
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According to the problem, we arrange four resistance as follows
Equivalent resistance $ = \frac{{20 \times 20}}{{40}} = 10\,\Omega $
Equivalent resistance $ = \frac{{20 \times 20}}{{40}} = 10\,\Omega $
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