Question
$\frac{40}{29}, \frac{141}{29}$
✓
Answer
$\frac{40}{29}, \frac{141}{29}$
Here, the denominators of the given numbers are the
same.
Since, $40<141$
$
\therefore \frac{40}{29}<\frac{141}{29}
$
Here, the denominators of the given numbers are the
same.
Since, $40<141$
$
\therefore \frac{40}{29}<\frac{141}{29}
$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following are perfect cube?1000
The curved surface area of a cylinder is $1320 cm^2$ and its base has diameter 21 cm . Find the height of the cylinder.
→Can the following figures be parallelograms. Justify your answer.
Find the least number which must be subtracted from the following numbers to make tham a perfact square:
$16160$
→$16160$
The capacity of a certain cuboidal tank is 50000 litres of water. Find the breadth of the tank if its height and length are 10 m and 2.5 m respectively.
Show that:
$\sqrt[3]{27}\times\sqrt[3]{64}=\sqrt[3]{27\times64}$
→$\sqrt[3]{27}\times\sqrt[3]{64}=\sqrt[3]{27\times64}$
Divide $72 a^4 b^5 c^8$ by $-9 a^2 b^2 c^3$.
→Observe the tables given below and in each case find whether x and y are inversely proportional.
| x | 9 |
3
|
6
|
36
|
| y |
4
|
12
|
9
|
1
|
Using the formula $(a+b)^2=\left(a^2+2 a b+b^2\right)$, evaluate:
$(630)^2$
→$(630)^2$
Evaluate:
$\sqrt[3]{\frac{27}{64}}$
→$\sqrt[3]{\frac{27}{64}}$