==> $\frac{{n'}}{n} = \sqrt {\frac{{T'}}{T}} \times \frac{l}{{l'}} = \sqrt 4 \times \frac{1}{2} = 1$
==> $n' = n$

${x_1} = a\sin (\omega \,t + {\phi _1})$, ${x_2} = a\sin \,(\omega \,t + {\phi _2})$
If in the resultant wave the frequency and amplitude remain equal to those of superimposing waves. Then phase difference between them is

${y_1} = 10\,\sin \,200\pi t$,
${y_2} = 20\,\sin \,\left( {2000\pi t + \frac{\pi }{2}} \right)$
are superimposed at any point at a particular instant. The amplitude of the resultant wave is