Question
From,
$1-5 y^2$, take away $y^3+7 y^2+y+1$
$1-5 y^2$, take away $y^3+7 y^2+y+1$
✓
Answer
Required expression:
$=\left(1-5 y^2\right)-\left(y^3+7 y^2+y+1\right)$
$=1-5 y^2-y^3-7 y^2-y-1$
$=-y^3-5 y^2-7 y^2-y$
$=-y^3-12 y^2-y$
$=\left(1-5 y^2\right)-\left(y^3+7 y^2+y+1\right)$
$=1-5 y^2-y^3-7 y^2-y-1$
$=-y^3-5 y^2-7 y^2-y$
$=-y^3-12 y^2-y$
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