MCQ
From $+6 $ to $+1 $ oxidation state is shown by the element of....... group
- A$V-B$
- ✓$VI-B$
- C$VII-B$
- D$VIII$
Maximum no. of ${e^ - }$ in last shell $= 6$
Group is $ VI-B.$
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$\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{g})$
the correct option is
$Zn(s) + Cu^{2+}(M) \to Zn^{2+}(M') + Cu(s);$ $E^o _{cell} = 1.10\,V$
$X$-axis :$log_{10}$ $\frac{{[Z{n^{2 + }}]}}{{[C{u^{2 + }}]}}$, $Y$ -axis : $E_{cell}$
$S{O_2} + N{O_2} \rightleftharpoons S{O_3} + NO$
If we take one mole of each of four gases in one $L$ container. What would be equilibrium concentration of $NO$ and $NO_2$ respectively