MCQ
From a building two balls $A$ and $B$ are thrown such that $A$ is thrown upwards and $B$ downwards (both vertically). If $v_{A}$ and $v_{B}$ are their respective velocities on reaching the ground, then
  • A
    $v_A > v_B$
  • $v_A = v_B$
  • C
    $v_A < v_B$
  • D
    their velocities depend on their masses

Answer

Correct option: B.
$v_A = v_B$
b
As the ball moves down from height $'h'$ to ground the $P.E.$ at height $'h'$ is converted to $K.E.$ at the ground (Applying Law of conservation of Energy).

Hence, $\frac{1}{2}{m_A}v_A^2 = {m_A}g{h_A}\,or\,{v_A} = \sqrt {2gh} \,;$

$similarly,\,{v_B} = \sqrt {2gh} \,\,or\,\,{v_A} = {v_B}$

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