Question
From the data given below state which group is more variable, $G_1$ or $G_2$?
Marks
$10-20$
$20-30$
$30-40$
$40-50$ $50-60$ $60-70$ $70-80$
Group $G_1$
$9$
$17$
$32$
$33$ $40$ $10$ $9$
Group $G_2$
$10$
$20$
$30$
$25$ $43$ $15$ $7$

Answer

Let's first find the coefficient of variable for Group $G_1$
CI f x $\text{u}=\frac{\text{x}-\text{A}}{\text{h}}$ fu $u^2$ $fu^2$
$10-20$ $9$ $15$ $-3$ $-27$ $9$ $81$
$20-30$ $17$ $25$ $-2$ $-34$ $4$ $68$
$30-40$ $32$ $35$ $-1$ $-32$ $1$ $32$
$40-50$ $33$ $45$ $0$ $0$ $0$ $0$
$50-60$ $40$ $55$ $1$ $40$ $1$ $40$
$60-70$ $10$ $65$ $2$ $20$ $4$ $40$
$70-80$ $9$ $75$ $3$ $27$ $9$ $81$
  $150$     $-6$   $342$
Here, $N = 150, A = 45$, $\sum\text{f}_\text{i}\text{u}_\text{i}=-6,\ \sum\text{f}_\text{i}\text{u}_\text{i}^2=342$ and $h = 10$
$\therefore\text{Mean}=\overline{\text{x}}=\text{A+h}\Big(\frac{1}{\text{N}}\sum\text{f}_\text{i}\text{u}_\text{i}\Big)$
$\Rightarrow\overline{\text{x}}=45+10\Big(\frac{-6}{150}\Big)=44.6$
$\text{Var}(\text{X})=\text{h}^2\bigg[\frac{1}{\text{N}}\sum\text{f}_\text{i}\text{u}_\text{i}^2-\Big(\frac{1}{\text{N}}\sum\text{f}_\text{i}\text{u}_\text{i}\Big)^2\bigg]$
$\text{Var}(\text{X})=100\bigg[\frac{342}{150}-\Big(\frac{-6}{150}\Big)^2\bigg]=227.84$
$\therefore\text{S.D.}=\sqrt{\text{Var}(\text{X})}=\sqrt{227.84}=15.09$
Coefficient of variation $=\frac{\text{S.D.}}{\overline{\text{x}}}\times100=\frac{15.09}{44.6}\times100=33.83$
Now, Let's first find the coefficient of variable for Group $G_2$
CI f x $\text{u}=\frac{\text{x}-\text{A}}{\text{h}}$ $fu$ $u^2$ $fu^2$
$10-20$ $10$ $15$ $-3$ $-30$ $9$ $902$
$20-30$ $20$ $25$ $-2$ $-40$ $4$ $80$
$30-40$ $30$ $35$ $-1$ $-30$ $1$ $30$
$40-50$ $25$ $45$ $0$ $0$ $0$ $0$
$50-60$ $43$ $55$ $1$ $43$ $1$ $43$
$60-70$ $15$ $65$ $2$ $30$ $4$ $60$
$70-80$ $7$ $75$ $3$ $21$ $9$ $63$
  $150$     $-6$   $366$
Here, $N = 150, A = 45$, $\sum\text{f}_\text{i}\text{u}_\text{i}=-6,\ \sum\text{f}_\text{i}\text{u}_\text{i}^2=366$ and $h = 10$
$\therefore\text{Mean}=\overline{\text{x}}=\text{A+h}\Big(\frac{1}{\text{N}}\sum\text{f}_\text{i}\text{u}_\text{i}\Big)$
$\Rightarrow\overline{\text{x}}=45+10\Big(\frac{-6}{150}\Big)=44.6$
$\text{Var}(\text{X})=\text{h}^2\bigg[\frac{1}{\text{N}}\sum\text{f}_\text{i}\text{u}_\text{i}^2-\Big(\frac{1}{\text{N}}\sum\text{f}_\text{i}\text{u}_\text{i}\Big)^2\bigg]$
$\text{Var}(\text{X})=100\bigg[\frac{366}{150}-\Big(\frac{-6}{150}\Big)^2\bigg]=243.84$
$\therefore\text{S.D.}=\sqrt{\text{Var}(\text{X})}=\sqrt{227.84}=15.62$
Coefficient of variation $=\frac{\text{S.D.}}{\overline{\text{x}}}\times100=\frac{15.09}{44.6}\times100=35.02$
$\therefore$ Group $G_2$ is more variable.

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