MCQ
From the point$ C(0,\lambda )$ two tangents are drawn to ellipse $x^2\ +\ 2y^2\ = 4$ cutting major axis at $A$ and $B$. If area of $\Delta$ $ABC$ is minimum, then value of $\lambda$ is-
- A$\sqrt 2 $
- ✓$2$
- C$2\sqrt 2 $
- D$8$
✓
Answer
Correct option: B.
$2$
b
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The distance of the point ($x_1, y_1$) from the origin:
→If $y + 3x = 0$ is the equation of a chord of the circle, $x^2 + y^2 - 30x = 0,$ then the equation of the circle with this chord as diameter is
→All possible two factors products are formed from numbers $1, 2, 3, 4, ...., 200$. The number of factors out of the total obtained which are multiples of $5$ is
→The position vectors of the four angular point of a tetrahedron OABC are (0, 0, 0), (0, 0, 2), (0, 4, 0) and (6, 0, 0) respectively. Find the coordinates of cenroid:
The number of ways 10 digit numbers can be written using the digits 1 and 2 is:
If $\cot\text{x}-\tan\text{x}=\sec\text{x},$ then, x is equal to:
→Consider the following lists:
→| $List-I$ | $List-II$ |
| ($I$) $\left\{x \in\left[-\frac{2 \pi}{3}, \frac{2 \pi}{3}\right]: \cos x+\sin x=1\right\}$ | ($P$) has two elements |
| ($II$) $\left\{x \in\left[-\frac{5 \pi}{18}, \frac{5 \pi}{18}\right]: \sqrt{3} \tan 3 x=1\right\}$ | ($Q$) has three elements |
| ($III$) $\left\{x \in\left[-\frac{6 \pi}{5}, \frac{6 \pi}{5}\right]: 2 \cos (2 x)=\sqrt{3}\right\}$ | ($R$) has four elements |
| ($I$) $\left\{x \in\left[-\frac{6 \pi}{5}, \frac{6 \pi}{5}\right]: 2 \cos (2 x)=\sqrt{3}\right\}$ | ($S$) has five elements |
| ($VI$) $\left\{x \in\left[-\frac{7 \pi}{4}, \frac{7 \pi}{4}\right]: \sin x-\cos x=1\right\}$ | ($T$) has six elements |
The correct option is:
The letters of the word '$MANKIND$' are written in all possible orders and arranged in serial order as in an English dictionary. Then the serial number of the word '$MANKIND$' is $.....$
→Locus of the point given by the equations $x = \frac{{2at}}{{1 + {t^2}}}$, $y = \frac{{a(1 - {t^2})}}{{1 + {t^2}}}\;\;( - 1 \le t \le 1)$ is a
→The solution set of the equation $pq{x^2} - {(p + q)^2}x + {(p + q)^2} = 0$ is
→