MCQ
From the $v-t$ graph, the
- Aspeed at $t = 1\,s$ is $1.2\, m/s$
- Bacceleration is $2\, m/s^2$
- ✓average speed during $1^{st}\, second$ is $1.5\, m/s$
- Dspeed of the particle can be zero
✓
Answer
Correct option: C.
average speed during $1^{st}\, second$ is $1.5\, m/s$
c
$v_{avg}=\frac{\text { distance }}{\text { time }}$
$v_{avg}=\frac{\text { distance }}{\text { time }}$
$v_{avg}=\frac{\frac{1}{2}(1+2) \times 1}{1}$
$=\frac{3}{2}=1.5 \mathrm{m} / \mathrm{s}$
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