Fusion reaction takes place at high temperature because - Vidyadip

MCQ

Fusion reaction takes place at high temperature because

A
nuclei break up at high temperature
B
atoms get ionised at high temperature
✓
kinetic energy is high enough to overcome the coulomb repulsion between nuclei
D
molecules break up at high temperature

✓

Answer

Correct option: C.

kinetic energy is high enough to overcome the coulomb repulsion between nuclei

c
Extremely high temperature needed for fusion make kinetic energy large enough to overcome coulomb repulsion between nuclei.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The kinetic energy, due to translational motion, of most of the molecules of an ideal gas at absolute temperature $T$ is

The ammeter reading in the circuit below is .............. $A$

Calculate the net resistance of the circuit between $A$ and $B$

The ratio of vapour densities of two gases at the same temperature is $\frac{4}{25}$, then the ratio of r.m.s. velocities will be :

Which of the curves in figure represents the relation between Celsius and Fahrenheit temperatures

The length and breadth of a rectangle are $(5.7 \pm 0.1) cm$ and $(3.4 \pm 0.2) cm$, respectively. Calculate the area of rectangle with error limits.

A potential difference of $2.5 \,V$ is applied across the faces of a germanium crystal plate. The face area of the crystal is $1 \,cm ^2$ and its thickness is $1.0 \,mm$. The free electron concentration in germanium is $2 \times 10^{19} \,m ^{-3}$ and the electron and holes mobilities are $0.33 \,m ^2 / s$ and $0.17 \,m ^2 / V$ s respectively. The current across the plate will be .......... $A$

$Assertion :$ The ratio of $\frac{C_p}{C_v}$ for an ideal diatomic gas is less than that for an ideal monoatomic gas (where $C_p$ and $C_v$ have usual meaning).
$Reason :$ The atoms of a monoatomic gas have less degrees of freedom as compared to molecules of the diatomic gas.

The magnitude of electric field intensity $E$ is such that, an electron placed in it would experience an electrical force equal to its weight is given by

$X-$ rays are produced due to