Question
Fusion reactions take lace at high temperature because:

Answer

  1. Kinetic energy is high enough to overcome repulsion between nuclei.
Explanation:
Extremely high temps needed for fusion because K.E. should large enough to overcome repulsion between nuclei.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

When a ray of light passes from a denser to a rarer medium:
The minimum wavelength of X-rays emitted by coolidge tube depends upon :
Two identical circular loops of metal wire are lying on a table without touching each other. Loop-A carries a current which increases with time. In response, the loop-B(a) Remains stationary(b) Is attracted by the loop-A(c) Is repelled by the loop-A(d) Rotates about its CM, with CM fixed
 
 
 
 
There are two coils A and B as shown in the figure. A current starts flowing in B as shown, when A is moved towards B and stops when A stops moving. The current in A is counter clockwise. B is kept stationary when A moves. We can infer that
Image
Consider a radioactive material of half$-$life $1.0$ minute. If one of the nuclei decays now, the next one will decay
An N-type semiconductor is:
When a magnetic field is applied in a direction perpendicular to the direction of cathode rays, then their(a) Energy decreases(b) Energy increases(c) Momentum increases(d) Momentum and energy remain unchanged
 
 
 
 
Thirteen resistances each of resistance $R$ ohm are connected in the circuit as shown in the figure below.  The effective resistance between $A$ and $B$ is
A magnet when placed perpendicular to a uniform field of strength $10^{-4} Wb / m ^2$  experiences a maximum couple of moment $4 \times 10^{-5} N / m$.. What is its magnetic moment
A potential difference of $42,000$ volts is used in an $X-$ray tube to accelerate electrons. The maximum frequency of the $X-$radiations produced is $(1 \ eV=1.6 \times 10^{-19} \mathrm{~J}$ and $ \mathrm{h}=6.63 \left.\times 10^{-34} \mathrm{~J}-\mathrm{sec}\right)$