f(x) = x^2 - 3x, then the points at which f(x) = f'(x) are - Vidyadip

MCQ

$f(x) = {x^2} - 3x$, then the points at which $f(x) = f'(x)$ are

A
$1, 3$
B
$1, -3$
C
$-1, 3$
✓
None of these

✓

Answer

Correct option: D.

None of these

d
(d) $f(x) = {x^2} - 3x$ and $f'(x) = 2x - 3$

But $f(x) = f'(x) \Rightarrow {x^2} - 3x = 2x - 3$

==> ${x^2} - 5x + 3 = 0$

$\therefore x = \frac{{5 \pm \sqrt {25 - 12} }}{2} = \frac{{5 \pm \sqrt {13} }}{2}$.

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