MCQ
$\text{f}(\text{x})=\sqrt{9-\text{x}^2}$. Find the range of the function:
  • A
    R
  • B
    R+
  • C
    [-3, 3]
  • D
    [0, 3]

Answer

  1. [0, 3]

Solution:

We know, square root is always non-negative.$\sqrt{9-\text{x}^2}>0$.

So, the range of the function is set of positive real numbers from 0 to 3.

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